A mouse jumps off from the 15 th floor of a h | vedclass

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Question

(d)

Given, distance of land from the building, $s=12 \,m$

Height of each floor, $h=3 \,m$

Total height of building,

$H=15 	imes 3=45 \,m$

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(d)

Given, distance of land from the building, $s=12 \,m$

Height of each floor, $h=3 \,m$

Total height of building,

$H=15 	imes 3=45 \,m$

The situation can be shown as,

Using second equation of motion for motion under gravity,

$H=u t+\frac{1}{2} g t^2=0+\frac{1}{2} g t^2$

$\Rightarrow \quad t=\sqrt{\frac{2 H}{g}}$

$=\sqrt{\frac{2 	imes 45}{10}}=3 \,s$

If $v$ be the horizontal speed, then

$s=v 	imes t$

$v=\frac{s}{t}$

$=\frac{12}{3}=4 \,ms ^{-1}$

$=4 	imes \frac{18}{5} \simeq 15 \,kmh ^{-1}$

A mouse jumps off from the $15$ th floor of a high-rise building and lands $12 \,m$ from the building. Assume that, each floor is of $3 \,m$ height. The horizontal speed with which the mouse jumps is closest to ...............$km /h$

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