A negative point charge placed at point A is

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2. Electric Potential and Capacitance

hard

A negative point charge placed at the point $A$ is

A

in stable equilibrium along $x-$axis

B

in unstable equilibrium along $x-$axis

C

in stable equilibrium along $y-$axis

D

$B$ and $C$ both

Solution

If the potential energy of the system is minimum, it will be stable equilibrium, i.e, $\frac{f^{2} U}{d x^{2}}>0$ and

when potential energy is maximum then it will be unstable equilibrium, i.e, $\frac{d^{2} U}{d x^{2}}<0$

As along y direction no electric field, potential energy is minimum and it will be stable

equilibrium along y-axis. Along $\mathrm{x}$ -axis potential energy is maximum due to all charges situated along $\mathrm{x}$ -axis.so it will be

unstable equilibrium.

Standard 12

Physics

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