Gujarati
Hindi
2. Electric Potential and Capacitance
medium

In the figure shown the electric potential energy of the system is: ( $q$ is at the centre of the conducting neutral spherical shell of inner radius $a$ and outer radius $b$ )

A

$0$

B

$\frac{{{\text{k}}{{\text{q}}^2}}}{{{\text{2b}}}}$

C

$\frac{{{\text{k}}{{\text{q}}^2}}}{{{\text{2b}}}} - \frac{{{\text{k}}{{\text{q}}^2}}}{{{\text{2a}}}}$

D

$\frac{{{\text{k}}{{\text{q}}^2}}}{{{\text{2a}}}} - \frac{{{\text{k}}{{\text{q}}^2}}}{{{\text{2b}}}}$

Solution

$U\, = \,\frac{{ – kqq}}{a}\, + \,\frac{{{\rm{kqq}}}}{b} – \,\frac{{{\rm{kqq}}}}{b} + \frac{{k{q^2}}}{{2a}} + \frac{{k{q^2}}}{{2b}} = \frac{{k{q^2}}}{{2b}} – \frac{{k{q^2}}}{{2a}}$

Standard 12
Physics

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