- Home
- Standard 11
- Physics
A one litre glass flask contains some mercury. It is found that at different temperatures the volume of air inside the flak remains the same. ...... $cc$ is the volume of mercury in this flask if coefficient of linear expansion of glass is $9 \times 10^{-6} /^o C$ while of volume expansion of mercury is $1.8 \times {10^4}\,/^\circ C$
$50$
$100$
$150$
$200$
Solution
(c) It is given that the volume of air in the flask remains the same.
This means that the expansion in volume of the vessel is exactly equal to the volume expansion of mercury.
i.e., $\Delta {V_g} = \Delta {V_L}$ or ${V_g}{\gamma _g}\Delta \theta = {V_L}{\gamma _L}\Delta \theta $
${V_L} = \frac{{{V_g}{\gamma _g}}}{{{\gamma _L}}} = \frac{{1000 \times (3 \times 9 \times {{10}^{ – 6}})}}{{1.8 \times {{10}^{ – 4}}}} = 150\,cc$