A parachutist of weight ‘w’ strikes ground with his legs fixed and comes to rest with an

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4-1.Newton's Laws of Motion

easy

A parachutist of weight $‘w’$ strikes the ground with his legs fixed and comes to rest with an upward acceleration of magnitude $3 \,g$. Force exerted on him by ground during landing is

A

$w$

B

$2w$

C

$3w$

D

$4w$

Solution

(d)Resultant force is $w + 3w = 4w$

Standard 11

Physics

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