Gujarati
Hindi
1. Electric Charges and Fields
normal

A parallel plate capacitor has a uniform electric field $E$ in the space between the plates. If the distance between the plates is $d$ and area of each plate is $A$ , the energy stored in the capacitor is

A

$\frac{1}{2}{\varepsilon _0}{E^2}Ad$

B

${\varepsilon _0}{E}Ad$

C

$\frac{1}{2}{\varepsilon _0}{E^2}$

D

${E^2}Ad/{\varepsilon _0}$

Solution

Energy density $=\frac{1}{2} \varepsilon_{0} \mathrm{E}^{2}$

So energy stored $=\frac{1}{2} \varepsilon_{0} \mathrm{E}^{2} \mathrm{Ad}$

Standard 12
Physics

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