Gujarati
Hindi
1. Electric Charges and Fields
normal

A parallel plate condenser has a uniform electric field $E(V/m)$ in the space between the plates. If the distance between the plates is $d(m)$ and area of each plate is $A(m^2)$, then the energy (joules) stored in the condenser is

A

${E^2}\,Ad/{ \in _0}$

B

$\frac{1}{2}{ \in _0}\,{E^2}$

C

${ \in _0}\,EAd$

D

$\frac{1}{2}{ \in _0}\,{E^2}\,Ad$

Solution

$Energy = \frac{1}{2}C{V^2} = \frac{1}{2}\left( {\frac{{A\,{ \in _0}}}{d}} \right){\left( {Ed} \right)^2} = \frac{1}{2}{ \in _0}{E^2}Ad$

Standard 12
Physics

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