Gujarati
Hindi
1. Electric Charges and Fields
normal

In the circuit shown in the figure, the potential difference across the $4.5\,\,\mu F$ capacitor is.......$volts$

                                

A

$2.67$

B

$4$

C

$6$

D

$8$

Solution

The given circuit can be redrawn as follow 

Potential difference across $4.5\, \mu \mathrm{F}$ capacitor

$\mathrm{V}=\frac{9}{\left(\frac{9}{2}+9\right)} \times 12=8 \mathrm{\,V}$

Standard 12
Physics

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