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1. Electric Charges and Fields
normal
In the circuit shown in the figure, the potential difference across the $4.5\,\,\mu F$ capacitor is.......$volts$
A
$2.67$
B
$4$
C
$6$
D
$8$
Solution

The given circuit can be redrawn as follow
Potential difference across $4.5\, \mu \mathrm{F}$ capacitor
$\mathrm{V}=\frac{9}{\left(\frac{9}{2}+9\right)} \times 12=8 \mathrm{\,V}$
Standard 12
Physics