A particle $A$ is projected vertically upwards. Another particle $B$ is projected at an angle of $45^{\circ}$. Both reach the same height. The ratio of the initial kinetic energy of $A$ to that of $B$ is
$1 : 2$
$2 : 1$
$1\,\,:\,\,\sqrt 2 $
$\sqrt 2 \,\,:\,\,1$
$A$ ball is projected vertically upwards. Air resistance variation in $g$ may be neglected. The ball rises to its maximum height $H$ in a time $T$, the height being $h$ after a time $t$
$[1]$ The graph of kinetic energy $E_k$ of the ball against height $h$ is shown in figure $1$
$[2]$ The graph of height $h$ against time $t$ is shown in figure $2$
$[3]$ The graph of gravitational energy $E_g$ of the ball against height $h$ is shown in figure $3$
Which of $A, B, C, D, E$ shows the correct answers?
A ball is projected from ground at an angle of $\theta $ from horizontal then graph of kinetic energy and time will be
A particle of mass $0.1 \,kg$ is subjected to a force which varies with distance as shown. If it starts its journey from rest at $x=0$, then its velocity at $x=12 \,m$ is .............. $m / s$
particle is projected from level ground. Its kinetic energy $K$ changes due to gravity so $\frac{{{K_{\max }}}}{{{K_{\min }}}} = 9$. The ratio of the range to the maximum height attained during its flight is
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