A particle describes a horizontal circle in a | vedclass

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Question

(d) The particle is moving in circular path

From the figure, $mg = R\sin 	heta $ &hellip;$(i)$

$\;\frac{{m{v^2}}}{r} = R\cos 	heta $ &hellip;$

Vedclass · Accepted Answer

$2.5 $

Vedclass · Answer

(d) The particle is moving in circular path

From the figure, $mg = R\sin 	heta $ &hellip;$(i)$

$\;\frac{{m{v^2}}}{r} = R\cos 	heta $ &hellip;$(ii)$

From equation $(i)$ and $(ii)$ we get

$	an 	heta = \frac{{rg}}{{{v^2}}}$  but $	an 	heta = \frac{r}{h}$

$h = \frac{{{v^2}}}{g} = \frac{{{{(0.5)}^2}}}{{10}} = 0.025m = 2.5\,cm$

A particle describes a horizontal circle in a conical funnel whose inner surface is smooth with speed of $0.5 \,m/s$. What is the height of the plane of circle from vertex of the funnel ........ $cm$

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