A particle is moving along a curve. Then
if its speed is constant it has no acceleration
the direction of its acceleration cannot be along the tangent.
if its speed is constant the magnitude of its acceleration is proportional to its curvature.
Both $(B)$ and $(C)$
A particle starts from rest and performing circular motion of constant radius with speed given by $v = \alpha \sqrt x$ where $\alpha$ is a constant and $x$ is the distance covered. The correct graph of magnitude of its tangential acceleration $(a_t)$ and centripetal acceleration $(a_c)$ versus $t$ will be:
A particle is moving with velocity $\vec v = K(y\hat i + x\hat j)$ where $K$ is a constant. The general equation for its path is
A particle has initial velocity $\left( {2\hat i + 3\hat j} \right)$ and acceleration $\left( {0.3\hat i + 0.2\hat j} \right)$. The magnitude of velocity after $10\, seconds$ will be
A body is moving with velocity $30\; m/s$ towards east. After $10$ seconds its velocity becomes $40\; m/s$ towards north. The average acceleration of the body is ...... $m/s^2$