A particle is moving along a straight line parallel to $x$-axis with constant velocity. Find angular momentum about the origin in vector form
$+m v^2 b \hat{k}$
$-m v b \hat{k}$
$-2 m v b \hat{k}$
$-m v b \hat{j}$
A ball of mass $1 \,kg$ is projected with a velocity of $20 \sqrt{2}\,m / s$ from the origin of an $x y$ co-ordinate axis system at an angle $45^{\circ}$ with $x$-axis (horizontal). The angular momentum [In $SI$ units] of the ball about the point of projection after $2 \,s$ of projection is [take $g=10 \,m / s ^2$ ] ( $y$-axis is taken as vertical)
A particle of mass $m$ is moving with constant velocity $v$ parallel to the $x$-axis as shown in the figure. Its angular momentum about origin $O$ is ..........
Explain Angular momentum of a particle and show that it is the moment of linear momentum about the reference point.
$A$ particle of mass $2\, kg$ located at the position $(\hat i + \hat j)$ $m$ has a velocity $2( + \hat i - \hat j + \hat k)m/s$. Its angular momentum about $z$ -axis in $kg-m^2/s$ is
Obtain $\tau = I\alpha $ from angular momentum of rigid body.