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3-2.Motion in Plane
medium
A particle is moving eastwards with a speed of $6 \,m / s$. After $6 \,s$, the particle is found to be moving with same speed in a direction $60^{\circ}$ north of east. The magnitude of average acceleration in this interval of time is ....... $m / s ^2$
A$6$
B$3$
C$1$
D$0$
Solution
(c)$|\Delta \vec{v}|=2 v \sin \frac{\theta}{2}=2 v \sin \left(\frac{60}{2}\right)=2 v \sin 30^{\circ}=v$
$|\Delta \vec{v}|=6 \,ms ^{-1}$
$\Delta t=6 \,s$
so, $a_{a v}=\frac{6}{6}=1 \,ms ^{-2}$
Standard 11
Physics
