A particle is moving in a vertical circle. tensions in string when passing through two positions at

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5.Work, Energy, Power and Collision

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A particle is moving in a vertical circle. The tensions in the string when passing through two positions at angles $30^o $ and $60^o $ from vertical (lowest position) are $T_1 and T_2$ respectively. then

A

$T_1 = T_2$

B

$T_2 > T_1$

C

$T_1 > T_2$

D

Tension in the string always remains the same

Solution

(c) Tension, $T = \frac{{m{v^2}}}{r} + mg\cos \theta $

For, $\theta = 30^\circ ,{T_1} = \frac{{m{v^2}}}{r} + mg\cos 30^\circ $

$\theta = 60^\circ ,{T_2} = \frac{{m{v^2}}}{r} + mg\cos 60^\circ $

$\therefore {T_1} > {T_2}$

Standard 11

Physics

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