Gujarati
5.Work, Energy, Power and Collision
medium

A body crosses the topmost point of a vertical circle with critical speed. Its centripetal acceleration, when the string is horizontal will be

A

$6\, g$

B

$3\, g$

C

$2\,g$

D

$g$

Solution

(b)$v = \sqrt {3gr} $ and $a = \frac{{{v^2}}}{r} = \frac{{3gr}}{r} = 3g$

Standard 11
Physics

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