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5.Work, Energy, Power and Collision
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A body crosses the topmost point of a vertical circle with critical speed. Its centripetal acceleration, when the string is horizontal will be
A
$6\, g$
B
$3\, g$
C
$2\,g$
D
$g$
Solution
(b)$v = \sqrt {3gr} $ and $a = \frac{{{v^2}}}{r} = \frac{{3gr}}{r} = 3g$
Standard 11
Physics
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