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3-1.Vectors
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A particle is moving with speed $6\,m/s$ along the direction of $\vec A = 2\hat i + 2\hat j - \hat k,$ then its velocity is
A
$(4\hat i + 2\hat j - 4\hat k)\,\,units$
B
$(4\hat i + 4\hat j - 2\hat k)\,\,units$
C
$(4\hat i + 4\hat j - 4\hat k)\,\,units$
D
$(2\hat i + 4\hat j - 2\hat k)\,\,units$
Solution
$\overrightarrow{\mathrm{v}} =|\overrightarrow{\mathrm{v}}| \hat{\mathrm{v}} $
$=6\left(\frac{2 \hat{\mathrm{i}}+2 \hat{\mathrm{j}}-\hat{\mathrm{k}}}{3}\right) $
$=4 \hat{\mathrm{i}}+4 \hat{\mathrm{j}}-2 \hat{\mathrm{k}}$
Standard 11
Physics
Similar Questions
A vector has a magnitude $x$. If it is rotated by an angle $\theta$, then magnitude of change in vector is $n x$. Match the following two columns.
| Colum $I$ | Colum $II$ |
| $(A)$ $\theta=60^{\circ}$ | $(p)$ $n=\sqrt{3}$ |
| $(B)$ $\theta=90^{\circ}$ | $(q)$ $n=1$ |
| $(C)$ $\theta=120^{\circ}$ | $(r)$ $n=\sqrt{2}$ |
| $(D)$ $\theta=180^{\circ}$ | $(s)$ $n=2$ |
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