A particle is projected from a point A with v | vedclass

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Question

Let $v$ be the velocity at the time of collision.

Then.        $u \sqrt{2} \cos 45^{\circ}=v \sin 60^{\circ}$

$\Rightarrow \

Vedclass · Accepted Answer

$\frac{{2u}}{{\sqrt 3 }}$

Vedclass · Answer

Let $v$ be the velocity at the time of collision.

Then.        $u \sqrt{2} \cos 45^{\circ}=v \sin 60^{\circ}$

$\Rightarrow \quad(u \sqrt{2})\left[\frac{1}{\sqrt{2}}ight]=\frac{\sqrt{3} v}{2}$

$	herefore \quad v=\frac{2}{\sqrt{3}} u$

A particle is projected from a point $A$ with velocity $u\sqrt 2$ at an angle of $45^o$ with horizontal as shown in fig. It strikes the plane $BC$ at right angles. The velocity of the particle at the time of collision is

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