Given below are two statements. One is labell | vedclass

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Question

For same range $	heta_{1}+	heta_{2}=90^{\circ}$

$h _{1} h _{2}=\frac{ u ^{2} \sin ^{2} 	heta_{1}}{2 g } 	imes \frac{ u ^{2} \sin ^{2} 	heta_{2

Vedclass · Accepted Answer

Both $A$ and $R$ are true and $R$ is the correct explanation of $A$.

Vedclass · Answer

For same range $	heta_{1}+	heta_{2}=90^{\circ}$

$h _{1} h _{2}=\frac{ u ^{2} \sin ^{2} 	heta_{1}}{2 g } 	imes \frac{ u ^{2} \sin ^{2} 	heta_{2}}{2 g }$

$	heta_{2}=90-	heta_{1}$

$h _{1} h _{2}=\frac{ u ^{2} \sin ^{2} 	heta_{1}}{2 g } \cdot \frac{ u ^{2} \cos ^{2} 	heta_{1}}{2 g }$

$=\left[\frac{ u ^{2} \sin 	heta_{1} \cos 	heta_{1}}{2 g }ight]^{2}$

$=\left[\frac{ u ^{2} \sin 	heta_{1} \cos 	heta_{1}}{2 g } 	imes \frac{2}{2}ight]^{2}=\frac{ R ^{2}}{16}$

$R =4 \sqrt{ h _{1} h _{2}}$

So $R$ is correct explanation of $A$

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