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A particle is projected from the ground with velocity $u$ at angle $\theta$ with horizontal. The horizontal range, maximum height and time of flight are $R, H$ and $T$ respectively. They are given by $R = \frac{{{u^2}\sin 2\theta }}{g}$, $H = \frac{{{u^2}{{\sin }^2}\theta }}{{2g}}$ and $T = \frac{{2u\sin \theta }}{g}$ Now keeping $u $ as fixed, $\theta$ is varied from $30^o$ to $60^o$. Then,
$R$ will first increase then decrease, $H$ will increase and $T$ will decrease
$R$ will first increase then decrease while $H$ and $T$ both will increase
$R$ will decrease while $H$ and $T$ will increase
$R$ will increase while $H$ and $T$ will increase
Solution
$R \propto \sin 2 \theta, H \propto \sin ^{2} \theta$ and $T \propto \sin \theta, \sin 2 \theta$ will first increase, then decrease. While sin $\theta$ will only increase.
Similar Questions
Trajectory of particle in a projectile motion is given as $y=x-\frac{x^2}{80}$. Here, $x$ and $y$ are in metre. For this projectile motion match the following with $g=10\,m / s ^2$.
| $Column-I$ | $Column-II$ |
| $(A)$ Angle of projection | $(p)$ $20\,m$ |
| $(B)$ Angle of velocity with horizontal after $4\,s$ | $(q)$ $80\,m$ |
| $(C)$ Maximum height | $(r)$ $45^{\circ}$ |
| $(D)$ Horizontal range | $(s)$ $\tan ^{-1}\left(\frac{1}{2}\right)$ |
