A particle moves along sides AB, BC, CD of a square of side 25 ,m with a velocity of 15 m{s^{ - 1}}.

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2.Motion in Straight Line

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A particle moves along the sides $AB, BC, CD$ of a square of side $25 \,m$ with a velocity of $15$$m{s^{ - 1}}.$ Its average velocity is........$m{s^{ - 1}}$

A

$15$

B

$10$

C

$7.5$

D

$5$

Solution

(d) Average velocity = $\frac{{{\rm{Total}}\,{\rm{displacement}}}}{{{\rm{Time}}\,\,{\rm{taken}}}}$$ = \frac{{25}}{{75/15}}$$=5m/s$

Standard 11

Physics

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