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2.Motion in Straight Line
medium
A particle moves for $8\, seconds$. It first accelerates from rest and then retards to rest. If the retardation be $3\, times$ the acceleration, then time for which it accelerates will be
A$2 $
B$3$
C$4$
D$6$
Solution
$\mathrm{v}=\alpha \mathrm{t}_{1}=\beta \mathrm{t}_{2} \quad \therefore \quad \frac{\alpha}{\beta}=\frac{\mathrm{t}_{2}}{\mathrm{t}_{1}}$
If $\beta=3 \alpha,$ then $t_{1}=3 t_{2}$
since, $t_{1}+t_{2}=8$ sec. $,$ hence $t_{1}=6$ sec.
If $\beta=3 \alpha,$ then $t_{1}=3 t_{2}$
since, $t_{1}+t_{2}=8$ sec. $,$ hence $t_{1}=6$ sec.
Standard 11
Physics
