A particle moves in x-y plane with velocity&n | vedclass

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Question

$\mathrm{V}_{\mathrm{x}}=\mathrm{a} \quad \mathrm{V}_{\mathrm{y}}=\mathrm{bx}$

${\int_{0}^{x} \mathrm{d} \mathrm{x}=\int_{0}^{\mathrm{t}} \mathrm{d

Vedclass · Accepted Answer

$y = \frac{{b{x^2}}}{{2a}}$

Vedclass · Answer

$\mathrm{V}_{\mathrm{x}}=\mathrm{a} \quad \mathrm{V}_{\mathrm{y}}=\mathrm{bx}$

${\int_{0}^{x} \mathrm{d} \mathrm{x}=\int_{0}^{\mathrm{t}} \mathrm{dt}}$               ${\mathrm{V}_{\mathrm{y}}=\mathrm{b} \mathrm{at}}$

${\mathrm{x}=\mathrm{at}}$          ${\int_{0}^{\mathrm{y}}\mathrm{dy}=\int_{0}^{\mathrm{t}} \mathrm{td} \mathrm{t}}$ 

 $y=a b \frac{(x / a)^{2}}{2}=\frac{b x^{2}}{2 a}$

A particle moves in $x-y$ plane with velocity $\vec v = a\widehat i\, + \,bx\widehat j$ where $a$ & $b$ are constants. Initially particle was at origin then trajectory equation is:-

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