Gujarati
Hindi
3-2.Motion in Plane
medium

A particle has initial velocity of $\left( {\widehat i + \widehat j} \right)\, m/s$ and an acceleration of $\left( {\widehat i + \widehat j} \right)\, m/s^2$. Its speed after $10s$ will be :-

A

$11\, m/s$

B

$22\, m/s$

C

$2 \sqrt {11}\, m/s$

D

$11\sqrt 2 \,m/s$

Solution

$\overrightarrow{\mathrm{v}}=\overrightarrow{\mathrm{u}}+\overrightarrow{\mathrm{a} t}$

$\overrightarrow{\mathrm{v}}=(\hat{\mathrm{i}}+\hat{\mathrm{j}})+(\hat{\mathrm{i}}+\hat{\mathrm{j}}) \cdot 10$

$\overrightarrow{\mathrm{v}}=11 \hat{\mathrm{i}}+11 \hat{\mathrm{j}}$

$|\overrightarrow{\mathrm{v}}|=11 \sqrt{2} \mathrm{m} / \mathrm{s}$

Standard 11
Physics

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