A particle moves in a circle of radius 25, cm | vedclass

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Question

$\begin{array}{l}
Here\,T = \frac{1}{2}\sec \,the\,required\,centripetal\
acceleration\,for\,moving\,in\,a\,circle\,is\
{a_C} = \frac{{{v^2}}}{r}

Vedclass · Accepted Answer

$4\,{\pi ^2}$

Vedclass · Answer

$\begin{array}{l}
Here\,T = \frac{1}{2}\sec \,the\,required\,centripetal\
acceleration\,for\,moving\,in\,a\,circle\,is\
{a_C} = \frac{{{v^2}}}{r} = \frac{{{{\left( {r\omega } ight)}^2}}}{r} = r{\omega ^2}r 	imes {\left( {2\pi /T} ight)^2}\
so\,{a_c} = 0.25 	imes {\left( {2\pi /0.5} ight)^2}\
\,\,\,\,\,\,\,\,\,\,\, = 16{\pi ^2} 	imes .25 = 4.0{\pi ^2}
\end{array}$

A particle moves in a circle of radius $25\, cm$ at two revolutions per second. The acceleration of the particle in $meter/second^2$ is

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