Gujarati
Hindi
5.Work, Energy, Power and Collision
normal

A particle moves under the effect of a force $F = cx$ from $x = 0$ to $x = x_1$. The work done in the process is

A

$cx_1^2$

B

$\frac{1}{2}cx_1^2$

C

$cx_1^3$

D

zero

Solution

Here $F=C x$

Work done $=\mathrm{F.d} \quad$ Where d is displacement

$w=\int_{x_{1}}^{x_{2}} F \cdot d x$

$w=\int_{0}^{x_{1}} F d x$

$w=\int_{0}^{x 1} c x d x$

$w=\frac{1}{2} c x_{1}^{2}$

Standard 11
Physics

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