Gujarati
3-2.Motion in Plane
medium

A particle moves with constant angular velocity in circular path of certain radius and is acted upon by a certain centripetal force $F$. if the centripetal force $F$ is kept constant but the angular velocity is doubled, the new radius of the path (original radius $R$ ) will be

A$2R$
B$R/2$
C$R/4$
D$4R$

Solution

(c) $F = m{\omega ^2}R$ $\therefore$ $R \propto \frac{1}{{{\omega ^2}}}$ ($m$ and $F$ are constant)
If $\omega$ is doubled then radius will become $1/4$ times i.e. $R/4$
Standard 11
Physics

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