2.Motion in Straight Line
hard

A particle moving in a straight line covers half the distance with speed $6 \mathrm{~m} / \mathrm{s}$. The other half is covered in two equal time intervals with speeds $9\ \mathrm{m} / \mathrm{s}$ and $15 \mathrm{~m} / \mathrm{s}$ respectively. The average speed of the particle during the motion is :

A$8.8 \mathrm{~m} / \mathrm{s}$
B$10 \mathrm{~m} / \mathrm{s}$
C$9.2 \mathrm{~m} / \mathrm{s}$
D$8 \mathrm{~m} / \mathrm{s}$
(JEE MAIN-2024)

Solution

$B D \Rightarrow S=9 t+15 t=24 t$
$A B \Rightarrow S=6 t_1=24 t \Rightarrow t_1=4 t$
$<\text { speed }>=\frac{\text { dist. }}{\text { time }}=\frac{48 t}{2 t+t_1}$
$=\frac{48 t}{2 t+4 t} \Rightarrow \frac{48 t}{6 t} \Rightarrow 8 \mathrm{~m} / \mathrm{s}$
Standard 11
Physics

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