A man walks on a straight road from his home to a market 2.5 km away with a speed of 5 km h ^{-1} .

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2.Motion in Straight Line

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A man walks on a straight road from his home to a market $2.5\; km$ away with a speed of $5 \;km h ^{-1} .$ Finding the market closed, he instantly turns and walks back home with a speed of $7.5 \;km h ^{-1} .$ What is the magnitude of average velocity in $m/s$?

A

$10$

B

$20$

C

$35$

D

$0$

Solution

Average velocity $=$ Total Displacement/Total Time $=0 m / s ^{2}$

Because, at the end displacement = $0 m$.

Standard 11

Physics

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