A particle moving with velocity v having specific charge $(q/m)$ enters a region of  magnetic field $B$ having width $d=\frac{{3mv}}{{5qB}}$ at angle $53^o$ to the boundary of magnetic field. Find the angle $\theta$ in the diagram......$^o$ 

131-190

  • A

    $37$

  • B

    $60$

  • C

    $90$

  • D

    none

Similar Questions

A particle having a mass of $10^{- 2} \,kg$ carries a charge of $5 \times 10^{-8}\, C.$ The particle is given an initial horizontal velocity of $10^5\, m/s $ in the presence of electric field $E$ and magnetic field  $B.$ To keep the particle moving in a horizontal direction, it is necessary that

$(1)$ $\vec B$ should be perpendicular to the direction of velocity and $\vec E$ should be along the direction of velocity
$(2)$  Both $\vec B$ and $\vec E$ should be along the direction of velocity
$(3)$ Both $\vec B$ and $\vec E$ are mutually perpendicular and perpendicular to the direction of velocity.
$(4)$ $\vec B$ should be along the direction of velocity and $\vec E$ should be perpendicular to the direction of velocity
Which one of the following pairs of statements is possible?

  • [AIPMT 2010]

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