An electron is accelerated by a potential difference of $12000\, volts$. It then enters a uniform magnetic field of ${10^{ - 3}}\,T$ applied perpendicular to the path of electron. Find the radius of path. Given mass of electron $ = 9 \times {10^{ - 31}}\,kg$ and charge on electron $ = 1.6 \times {10^{ - 19}}\,C$

  • A

    $36.7\, m$

  • B

    $36.7\, cm$

  • C

    $3.67\, m$

  • D

    $3.67\, cm$

Similar Questions

A particle having a mass of $10^{- 2} \,kg$ carries a charge of $5 \times 10^{-8}\, C.$ The particle is given an initial horizontal velocity of $10^5\, m/s $ in the presence of electric field $E$ and magnetic field  $B.$ To keep the particle moving in a horizontal direction, it is necessary that

$(1)$ $\vec B$ should be perpendicular to the direction of velocity and $\vec E$ should be along the direction of velocity
$(2)$  Both $\vec B$ and $\vec E$ should be along the direction of velocity
$(3)$ Both $\vec B$ and $\vec E$ are mutually perpendicular and perpendicular to the direction of velocity.
$(4)$ $\vec B$ should be along the direction of velocity and $\vec E$ should be perpendicular to the direction of velocity
Which one of the following pairs of statements is possible?

  • [AIPMT 2010]

Under the influence of a uniform magnetic field a charged particle is moving in a circle of radius $R$ with constant speed $v$. The time period of the motion

  • [AIPMT 2009]

The radius of circular path of an electron when subjected to a perpendicular magnetic field is

An electron is travelling horizontally towards east. A magnetic field in vertically downward direction exerts a force on the electron along

If an electron is going in the direction of magnetic field $\overrightarrow B $ with the velocity of $\overrightarrow {v\,} $ then the force on electron is