A particle of mass $m$ is projected at $45^o$ at $V_0$ speed from point $P$ at $t = 0$. The angular momnetum of particle about $P$ at $t = \frac{V_0}{g}$ is:-
A particle of mass $m$ is projected at $45^o$ at $V_0$ speed from point $P$ at $t = 0$. The angular momnetum of particle about $P$ at $t = \frac{V_0}{g}$ is:-
- A
$\frac{1}{2 \sqrt 2} \frac{mV_0^3}{g}$
- B
$\frac{1}{2 \sqrt 2} \frac{mV_0^2}{g}$
- C
$\frac{1}{2} \frac{mV_0^3}{g}$
- D
$\frac{1}{2} \frac{mV_0^2}{g}$
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