$A$ paritcle falls freely near the surface of the earth. Consider $a$ fixed point $O$ (not vertically below the particle) on the ground.
Angular momentum of the particle about $O$ is increasing .
The angular velocity of the particle about $O$ is increasing.
The moment of inertia of the particle about $O$ is decreasing .
All of the above
A particle of mass $m = 5$ is moving with a uniform speed $v = 3\sqrt 2$ in the $XOY$ plane along the line $Y = X + 4$ . The magnitude of the angular momentum of the particle about the origin is .......
A particle is moving along a straight line parallel to $x$-axis with constant velocity. Find angular momentum about the origin in vector form
A particle of mass $20\,g$ is released with an initial velocity $5\,m/s$ along the curve from the point $A,$ as shown in the figure. The point $A$ is at height $h$ from point $B.$ The particle slides along the frictionless surface. When the particle reaches point $B,$ its angular momentum about $O$ will be ......... $kg - m^2/s$. [Take $g = 10\,m/s^2$ ]
$A$ particle of mass $2\, kg$ located at the position $(\hat i + \hat j)$ $m$ has a velocity $2( + \hat i - \hat j + \hat k)m/s$. Its angular momentum about $z$ -axis in $kg-m^2/s$ is
Angular momentum of a single particle moving with constant speed along circular path: