A particle of mass M is placed at centre of a uniform spherical shell of mass 2M and radius R .

English

Gujarati

Hindi

7.Gravitation

normal

A particle of mass $M$ is placed at the centre of a uniform spherical shell of mass $2M$ and radius $R$. The gravitational potential on the surface of the shell is

A

$-\frac{GM}{R}$

B

$-\frac{3GM}{R}$

C

$-\frac{2GM}{R}$

D

Zero

Solution

$\therefore \mathrm{V}_{\text {Surface }}=\mathrm{V}_{\text {Shell }}+\mathrm{V}_{\mathrm{M}}$

${=\frac{-G[2 M]}{R}-\frac{G M}{R}}$

${=-\frac{3 G M}{R}}$

Standard 11

Physics

Share

Similar Questions

Assume that a tunnel is dug through earth from North pole to south pole and that the earth is a non-rotating, uniform sphere of density $\rho $. The gravitational force on a particle of mass $m$ dropped into the tunnel when it reaches a distance $r$ from the centre of earth is

normal

The force of gravitation is

normal

The two planets have radii $r_1$ and $r_2$ and their densities $p_1$ and $p_2$ respectively. The ratio of acceleration due to gravity on them will be

normal

If the acceleration due to gravity at earth is $'g'$ and mass of earth is $80$ times that of moon and radius of earth is $4$ times that of moon, the value of acceleration due to gravity at the surface of moon will be

normal

Time period of simple pendulum increases by an amount $\sqrt 2 $ times at height $'h'$ from the surface of earth. Then the value of $h$ is

normal