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7.Gravitation
normal
If the acceleration due to gravity at earth is $'g'$ and mass of earth is $80$ times that of moon and radius of earth is $4$ times that of moon, the value of acceleration due to gravity at the surface of moon will be
A
$g$
B
$g/20$
C
$g/5$
D
$320\,g$
Solution
$\mathrm{G}_{\mathrm{moon}}=\frac{\mathrm{GMm}}{\mathrm{R}_{\mathrm{M}}^{2}}=\frac{\mathrm{G}(\mathrm{Me} / 80)}{(\mathrm{Re} / 4)^{2}}$
$=\frac{1}{5} \frac{\mathrm{GMe}}{\mathrm{Re}^{2}}=\frac{\mathrm{g}}{5}$
Standard 11
Physics