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4-1.Newton's Laws of Motion
easy
A particle of mass $m$ is moving with a uniform velocity $v_1$. It is given an impulse such that its velocity becomes $v_2$. The impulse is equal to
A
$m\left[v_{2}-v_{1}\right]$
B
$m\left[v_{1}+v_{2}\right]$
C
$\frac{1}{2} m\left[\left|v_{2}^{2}\right|-\left|v_{1}^{2}\right|\right]$
D
$m\left[\left|v_{2}\right|-\left|v_{1}\right|\right]$
(AIPMT-1990)
Solution
Impulse is a vector quantity and is equal to change in momentum of the body
Impulse $=m v_{2}-m v_{1}=m\left(v_{2}-v_{1}\right)$
Standard 11
Physics
