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3-2.Motion in Plane
easy
A particle of mass $m$ is executing uniform circular motion on a path of radius $r$. If $p$ is the magnitude of its linear momentum. The radial force acting on the particle is
A$pmr$
B$\frac{{rm}}{p}$
C$\frac{{m{p^2}}}{r}$
D$\frac{{{p^2}}}{{rm}}$
Solution
(d)Radial force $ = \frac{{m{v^2}}}{r} = \frac{m}{r}{\left( {\frac{p}{m}} \right)^2} = \frac{{{p^2}}}{{mr}}$ [As $p = mv$]
Standard 11
Physics
