A single wire ACB passes through a smooth&nbs | vedclass

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Question

Force equation from ring frame along $y-axis$

$\mathrm{T} \cos 30^{\circ}+\mathrm{T} \cos 60^{\circ}=\mathrm{mg}$

$\mathrm{T} 	imes\left(\frac{

Vedclass · Accepted Answer

$\sqrt{rg}$

Vedclass · Answer

Force equation from ring frame along $y-axis$

$\mathrm{T} \cos 30^{\circ}+\mathrm{T} \cos 60^{\circ}=\mathrm{mg}$

$\mathrm{T} 	imes\left(\frac{\sqrt{3}+1}{2}ight)=\mathrm{mg}$          $...(i)$

along $x-axis$

$\mathrm{T} \sin 30^{\circ}+\mathrm{T} \sin 60^{\circ}=\frac{\mathrm{mv}^{2}}{\mathrm{r}}$

$\mathrm{T}\left(\frac{\sqrt{3}+1}{2}ight)=\frac{\mathrm{mv}^{2}}{\mathrm{r}}$        $...(ii)$

$(ii)$ $/( i)$ we get

$\mathrm{v}=\sqrt{\mathrm{rg}}$

A single wire $ACB$ passes through a smooth ring at $C$ which revolves at a constant speed in the horizontal circle of radius $r$ as shown in the figure. The speed of revolution is

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