A particle when thrown, moves such that it passes from same height at 2 and 10s , height is

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2.Motion in Straight Line

hard

A particle when thrown, moves such that it passes from same height at $2$ and $10s$, the height is

A

$g$

B

$2g$

C

$5g$

D

$10g$

Solution

(d) If ${t_1}$ and ${t_2}$are the time, when body is at the same height then,

$h = \frac{1}{2}g\,{t_1}{t_2}$ $ = \frac{1}{2} \times g \times 2 \times 10 = 10\;g$

Standard 11

Physics

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