Gujarati
Hindi
4.Moving Charges and Magnetism
normal

A particle with charge $+Q$ and mass m enters a magnetic field of magnitude $B,$ existing only to the right of the boundary $YZ$. The direction of the motion of the $m$ particle is perpendicular to the direction of $B.$ Let $T = 2\pi\frac{m}{{QB}}$ . The time spent by the particle in the field will be 

A

$T\theta$

B

$2T\theta$

C

$T \left( {\frac{{\pi  + 2\theta }}{{2\pi }}} \right)$

D

$T \left( {\frac{{\pi  - 2\theta }}{{2\pi }}} \right)$

Solution

A particle having charge $+Q,$ mass $=m$ Magnetic field $=B$

$T=\frac{m}{Q B}$

Therefore, The time spent by the particle in the field will be$:$

$T\left(\frac{\pi+2 \theta}{2 \pi}\right)$

Standard 12
Physics

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