Gujarati
Hindi
4.Moving Charges and Magnetism
normal

A particle with charge $-Q$ and mass m enters a magnetic field of magnitude $B,$ existing only to the right of the boundary $YZ$. The direction of the motion of the $m$ particle is perpendicular to the direction of $B.$ Let $T = 2\pi\frac{m}{{QB}}$ . The time spent by the particle in the field will be 

A

$T\theta$

B

$2T\theta$

C

$T\left( {\frac{{\pi  + 2\theta }}{{2\pi }}} \right)$

D

$T\left( {\frac{{\pi  - 2\theta }}{{2\pi }}} \right)$

Solution

$\boldsymbol{\alpha}=\pi-2 \boldsymbol{\theta}$

$t=\frac{T}{2 \pi}(\pi-2 \theta)$

Standard 12
Physics

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