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4.Moving Charges and Magnetism
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Two charged particles, having same kinetic energy, are allowed to pass through a uniform magnetic field perpendicular to the direction of motion. If the ratio of radii of their circular paths is $6: 5$ and their respective masses ratio is $9: 4$. Then, the ratio of their charges will be.
A
$8: 5$
B
$5: 4$
C
$5: 3$
D
$8: 7$
(JEE MAIN-2022)
Solution
Radius of circular path $R =\frac{\sqrt{2 mk }}{ qB }$
$q =\frac{\sqrt{2 mk }}{ RB }$
$\frac{ q _{1}}{ q _{2}}=\sqrt{\frac{ m _{1}}{ m _{2}}} \times \frac{ R _{2}}{ R _{1}}=\sqrt{\frac{9}{4}} \times \frac{5}{6}=\frac{5}{4}$
Standard 12
Physics
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