A pendulum of length l = 1,m is released from θ _0 = 60^o. rate of change of speed of bob at ?

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5.Work, Energy, Power and Collision

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A pendulum of length $l = 1\,m$ is released from $\theta _0 = 60^o.$ The rate of change of speed of the bob at $\theta = 30^o$ is ........ $m/s^2$ $(g = 10\,m/s^2)$

A

$5\sqrt 3$

B

$5$

C

$10$

D

$2.5$

Solution

$a_{T}=g \cos 60^{\circ}$

$a_{T}=g / 2$

Standard 11

Physics

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