A planet is revolving ground the sun in an elliptical orbit. Its closest distance from the sun is $r_{min}$, the farthest distance from the sun is $r_{max}$. If the orbital angular velocity of the planet when it is the nearest to the sun is $\omega $, then the orbital angular velocity at the point when it is at the farthest distance from the sun is 

  • A

    $\sqrt {\frac{{{r_{min}}}}{{{r_{\max }}}}} \,\omega $

  • B

    $\sqrt {\frac{{{r_{\max }}}}{{{r_{\min }}}}} \,\omega $

  • C

    $\frac{{{r^2}_{\max }}}{{{r^2}_{\min }}}\,\omega $

  • D

    $\frac{{{r^2}_{min}}}{{{r^2}_{\max }}}\,\omega $

Similar Questions

In order to shift a body of mass $m$ from a circular orbit of radius $3R$ to a higher radius $5R$ around the earth, the work done is

The value of escape velocity on a certain planet is $2\, km/s$ . Then the value of orbital speed for a satellite orbiting close to its surface is

A skylab of mass $m\,kg$ is first launched from the surface of the earth in a circular orbit of radius $2R$ (from the centre of the earth) and then it is shifted from this circular orbit to another circular orbit of radius $3R$ . The minimum energy required to shift the lab from first orbit to the second orbit are

Three identical bodies of equal mass $M$ each are moving along a circle of radius $R$ under the action of their mutual gravitational attraction. The speed of each body is

The minimum and maximum distances of a planet revolving around the Sun are $x_{1}$ and $x_{2}$. If the minimum speed of the planet on its trajectory is $v_o$ then its maximum speed will be

  • [JEE MAIN 2021]