A particle of mass m strikes a wall with speed v at an angle 30^{circ} with wall elastically as show

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4-1.Newton's Laws of Motion

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A particle of mass $m$ strikes a wall with speed $v$ at an angle $30^{\circ}$ with the wall elastically as shown in the figure. The magnitude of impulse imparted to the ball by the wall is

A

$m v$

B

$\frac{m v}{2}$

C

$2 m v$

D

$\sqrt{3} m v$

Solution

(a)

Impulse = change in momentum

applying equation of change in momentum in horizontal direction

$I=m v \sin 30^{\circ}-\left(-m v \sin 30^{\circ}\right)$

$=2 m v\left(\frac{1}{2}\right)=m v$

Standard 11

Physics

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