4-1.Newton's Laws of Motion
medium

A player caught a cricket ball of mass $150\ \mathrm{~g}$ moving at a speed of $20\ \mathrm{~m} / \mathrm{s}$. If the catching process is completed in $0.1\ \mathrm{~s}$, the magnitude of force exerted by the ball on the hand of the player is .......... $N$

A$150$
B$3$
C$30$
D$300$
(JEE MAIN-2024) (AIEEE-2006) (AIPMT-2001)

Solution

$\mathrm{F}=\frac{\Delta \mathrm{P}}{\Delta \mathrm{t}}=\frac{\mathrm{mv}-0}{0.1}$
$=\frac{150 \times 10^{-3} \times 20}{0.1}=30 \mathrm{~N}$
Standard 11
Physics

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