A player caught a cricket ball of mass 150 g moving at a rate of 20 m/s .If catching process is comp

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4-1.Newton's Laws of Motion

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A player caught a cricket ball of mass $150\ g$ moving at a rate of $20\ m/s$.If the catching process is completed in $0.1\ s $, the force of the blow exerted by the ball on the hand of the player is equal to .......... $N$

A$300$

B$150$

C$3$

D$30$

Solution

$F = \frac{{m \left( {v – u} \right)}}{t} = \frac{{0.15\left( {0 – 20} \right)}}{{0.1}} = 30N$

Standard 11

Physics

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