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2. Electric Potential and Capacitance
medium
A point charge $2 \times 10^{-2}\,C$ is moved from $P$ to $S$ in a uniform electric field of $30\,NC ^{-1}$ directed along positive $x$-axis. If coordinates of $P$ and $S$ are $(1,2$, $0) m$ and $(0,0,0) m$ respectively, the work done by electric field will be $.........\,mJ$
A$1200$
B$600$
C$-600$
D$-1200$
(JEE MAIN-2023)
Solution

$=2 \times 10^{-2}[30 \hat{ i } \cdot(-\hat{ i })]$
$=2 \times 10^{-2}(-30)$
$=-60 \times 10^{-2}$
$=-\frac{60}{100}=-0.6\,J$
$=-600\,mJ$
Standard 12
Physics