A positive charge $q$ is kept at the center of a thick shell of inner radius $R_1$ and outer radius $R_2$ which is made up of conducting material. If $\phi_1$ is flux through closed gaussian surface $S_1$ whose radius is just less than $R_1$ and $\phi_2$ is flux through closed gaussian surface $S_2$ whose radius is just greater than $R_1$ then:-
$\phi_1 > \phi_2$
$\phi_2 > \phi_1$
$\phi_1 = \phi_2 = \frac {q}{\varepsilon_0}$
$\phi_1 = \phi_2 = \frac {kq}{\varepsilon_0}$
A charged particle $q$ is placed at the centre $O$ of cube of length $L$ $(A\,B\,C\,D\,E\,F\,G\,H)$. Another same charge $q$ is placed at a distance $L$ from $O$.Then the electric flux through $BGFC$ is
Five charges $+q,+5 q,-2 q,+3 q$ and $-4 q$ are situated as shown in the figure.
The electric flux due to this configuration through the surface $S$ is
A hollow cylinder has a charge $q$ coulomb within it. If $\phi$ is the electric flux in units of $volt-meter$ associated with the curved surface $B,$ the flux linked with the plane surface $A$ in units of $V-m$ will be
A charge $Q$ is fixed at a distance $d$ in front of an infinite metal plate. The lines of force are represented by
If $\oint_s \vec{E} \cdot \overrightarrow{d S}=0$ over a surface, then: