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1. Electric Charges and Fields
medium
A cone of base radius $R$ and height $h$ is located in a uniform electric field $\vec E$ parallel to its base. The electric flux entering the cone is
A
$\frac{1}{2}\,EhR$
B
$E h R$
C
$2\, E h R$
D
$4\, E h R$
(JEE MAIN-2014)
Solution
Electric flux, $\phi \, = E \,(ds)\, cos\, \theta$
$= E \,(hR)\, cos\, 0^o\, = EhR$
Standard 12
Physics