A cone of base radius $R$ and height $h$ is located in a uniform electric field $\vec E$ parallel to its base. The electric flux entering the cone is
A cone of base radius $R$ and height $h$ is located in a uniform electric field $\vec E$ parallel to its base. The electric flux entering the cone is
- [JEE MAIN 2014]
- A
$\frac{1}{2}\,EhR$
- B
$E h R$
- C
$2\, E h R$
- D
$4\, E h R$
Similar Questions
A cube is placed inside an electric field, $\overrightarrow{{E}}=150\, {y}^{2}\, \hat{{j}}$. The side of the cube is $0.5 \,{m}$ and is placed in the field as shown in the given figure. The charge inside the cube is $.....\times 10^{-11} {C}$
A cube is placed inside an electric field, $\overrightarrow{{E}}=150\, {y}^{2}\, \hat{{j}}$. The side of the cube is $0.5 \,{m}$ and is placed in the field as shown in the given figure. The charge inside the cube is $.....\times 10^{-11} {C}$
- [JEE MAIN 2021]
When electric flux is said to be positive, negative or zero ?
When electric flux is said to be positive, negative or zero ?
For a given surface the Gauss's law is stated as $\oint {E \cdot ds} = 0$. From this we can conclude that
For a given surface the Gauss's law is stated as $\oint {E \cdot ds} = 0$. From this we can conclude that
Draw electric field by negative charge.
Draw electric field by negative charge.
An electric field converges at the origin whose magnitude is given by the expression $E = 100\,r\,Nt/Coul$, where $r$ is the distance measured from the origin.
An electric field converges at the origin whose magnitude is given by the expression $E = 100\,r\,Nt/Coul$, where $r$ is the distance measured from the origin.