1. Electric Charges and Fields
medium

A cone of base radius $R$ and height $h$ is located in a uniform electric field $\vec E$ parallel to its base. The electric flux entering the cone is

A

$\frac{1}{2}\,EhR$

B

$E h R$

C

$2\, E h R$

D

$4\, E h R$

(JEE MAIN-2014)

Solution

Electric flux, $\phi \, = E \,(ds)\, cos\, \theta$

$= E \,(hR)\, cos\, 0^o\, = EhR$

Standard 12
Physics

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