A projectile cover double range as compare to its maximum height attained. angle of

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3-2.Motion in Plane

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A projectile cover double range as compare to its maximum height attained. The angle of projection is

A

$\tan^{-1} \,2$

B

$\tan^{-1} \,4$

C

$\tan^{-1} \,3$

D

$\tan^{-1} \,5$

Solution

$\frac{\mathrm{h}}{\mathrm{R}}=\frac{\tan \theta}{4}$

$\frac{1}{2}=\frac{\tan \theta}{4}$

$\tan \theta=2$

$\theta=\tan ^{-1} 2$

Standard 11

Physics

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